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# Solving Volume Problems

What we need here is to get a formula for the cross-sectional area at any $$x$$.

For example, the Pyramid of Cestius, in Rome, Italy, is an example of a pyramid with a rectangular base.\right|_0^h = \pi h\] So, we get the expected formula.Also, recall we are using $$r$$ to represent the radius of the cylinder.You can see in the picture that the lateral faces are triangles, and that the edges of the lateral faces all meet at one point at the top, or vertex, of the pyramid.In this lesson, you solved problems involving the volume of rectangular pyramids and triangular pyramids.All other letters in the integral should be thought of as constants.If you have trouble doing that, just think about what you’d do if the $$r$$ was a 2 or the $$h$$ was a 3 for example.All of the examples in this section are going to be more general derivation of volume formulas for certain solids.As such we’ll be working with things like circles of radius $$r$$ and we’ll not be giving a specific value of $$r$$ and we’ll have heights of $$h$$ instead of specific heights, .As you noticed, there are also many other types of pyramids.However, you will learn more about determining the volumes of those pyramids in later courses.